(2y^2+3y-7)+(5-3y+y^2)=

Solution for (2y^2+3y-7)+(5-3y+y^2)= equation:

Simplifying
(2y2 + 3y + -7) + (5 + -3y + y2) = 0

Reorder the terms:
(-7 + 3y + 2y2) + (5 + -3y + y2) = 0

Remove parenthesis around (-7 + 3y + 2y2)
-7 + 3y + 2y2 + (5 + -3y + y2) = 0

Remove parenthesis around (5 + -3y + y2)
-7 + 3y + 2y2 + 5 + -3y + y2 = 0

Reorder the terms:
-7 + 5 + 3y + -3y + 2y2 + y2 = 0

Combine like terms: -7 + 5 = -2
-2 + 3y + -3y + 2y2 + y2 = 0

Combine like terms: 3y + -3y = 0
-2 + 0 + 2y2 + y2 = 0
-2 + 2y2 + y2 = 0

Combine like terms: 2y2 + y2 = 3y2
-2 + 3y2 = 0

Solving
-2 + 3y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 3y2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 3y2 = 0 + 2
3y2 = 0 + 2

Combine like terms: 0 + 2 = 2
3y2 = 2

Divide each side by '3'.
y2 = 0.6666666667

Simplifying
y2 = 0.6666666667

Take the square root of each side:
y = {-0.816496581, 0.816496581}